An inequality for Kruskal-Macaulay functions

Abstract

Given integers k≥1 and n≥0, there is a unique way of writing n as n=nkk+nk-1k-1+...+n11 so that 0≤ n1<...<nk-1<nk. Using this representation, the Kruskal-Macaulay function ofn is defined as ∂k(n) =nk-1k-1+nk-1-1k-2+...+n1-1% 0. We show that if a≥0 and a<∂k+1(n) , then ∂k(a) +∂k+1(n-a) ≥ ∂k+1(n) . As a corollary, we obtain a short proof of Macaulay's Theorem. Other previously known results are obtained as direct consequences.

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