When are two Dedekind sums equal?

Abstract

A natural question about Dedekind sums is to find conditions on the integers a1, a2, and b such that s(a1,b) = s(a2, b). We prove that if the former equality holds then b \ | \ (a1a2-1)(a1-a2). Surprisingly, to the best of our knowledge such statements have not appeared in the literature. A similar theorem is proved for the more general Dedekind-Rademacher sums as well, namely that for any fixed non-negative integer n, a positive integer modulus b, and two integers a1 and a2 that are relatively prime to b, the hypothesis rn (a1,b)= rn (a2,b) implies that b \ | \ (6n2+1-a1a2)(a2-a1).

0

Turn this paper into a lesson

ArcXiv compiles a structured reading guide from this paper's metadata: plain-English importance, contributions, prerequisite concepts, which sections to read first, flashcards, and a quiz. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…