Optical spectroscopy shows that the normal state of URu2Si2 is an anomalous Fermi liquid

Abstract

Fermi showed that electrons, as a result of their quantum nature, form a gas of particles where the temperature and density follow the so called Fermi distribution. In a metal, as shown by Landau, that despite their strong Coulomb interaction with each other and the positive background ions, the electrons continue to act like free quantum mechanical particles but with enhanced masses. This state of matter, the Landau-Fermi liquid, is recognized experimentally by an electrical resistivity that is proportional to the square of the absolute temperature plus a term proportional to the square of the frequency of the applied field. Calculations show that, if electron-electron scattering dominates the resistivity in a Landau Fermi liquid, the ratio of the two terms, b has the universal value of b = 4. We find that in the normal state of the heavy Fermion metal URu2Si2, instead of the Fermi liquid value of 4 the coefficient b =1 0.1. This unexpected result implies that the electrons in this material are experiencing a unique scattering process. This scattering is intrinsic and we suggest that, the uranium f electrons do not hybridize to form a coherent Fermi liquid but instead act like a dense array of elastic impurities, interacting incoherently with the charge carriers. This behavior is not restricted to URu2Si2. Fermi liquid like states with b ≠ 4 have been observed in a number of disparate systems but the significance of this result has not been recognized.

0

Turn this paper into a lesson

ArcXiv compiles a structured reading guide from this paper's metadata: plain-English importance, contributions, prerequisite concepts, which sections to read first, flashcards, and a quiz. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…