What is Ramsey-equivalent to a clique?

Abstract

A graph G is Ramsey for H if every two-colouring of the edges of G contains a monochromatic copy of H. Two graphs H and H' are Ramsey-equivalent if every graph G is Ramsey for H if and only if it is Ramsey for H'. In this paper, we study the problem of determining which graphs are Ramsey-equivalent to the complete graph Kk. A famous theorem of Nesetril and Rodl implies that any graph H which is Ramsey-equivalent to Kk must contain Kk. We prove that the only connected graph which is Ramsey-equivalent to Kk is itself. This gives a negative answer to the question of Szabo, Zumstein, and Zurcher on whether Kk is Ramsey-equivalent to Kk.K2, the graph on k+1 vertices consisting of Kk with a pendent edge. In fact, we prove a stronger result. A graph G is Ramsey minimal for a graph H if it is Ramsey for H but no proper subgraph of G is Ramsey for H. Let s(H) be the smallest minimum degree over all Ramsey minimal graphs for H. The study of s(H) was introduced by Burr, Erdos, and Lovasz, where they show that s(Kk)=(k-1)2. We prove that s(Kk.K2)=k-1, and hence Kk and Kk.K2 are not Ramsey-equivalent. We also address the question of which non-connected graphs are Ramsey-equivalent to Kk. Let f(k,t) be the maximum f such that the graph H=Kk+fKt, consisting of Kk and f disjoint copies of Kt, is Ramsey-equivalent to Kk. Szabo, Zumstein, and Zurcher gave a lower bound on f(k,t). We prove an upper bound on f(k,t) which is roughly within a factor 2 of the lower bound.

0

Turn this paper into a lesson

ArcXiv compiles a structured reading guide from this paper's metadata: plain-English importance, contributions, prerequisite concepts, which sections to read first, flashcards, and a quiz. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…