New congruences involving harmonic numbers

Abstract

Let p>3 be a prime. For any p-adic integer a, we determine Σk=0p-1-aka-1kHk,\ \ Σk=0p-1-aka-1kHk(2),\ \ Σk=0p-1-aka-1kHk(2)2k+1 modulo p2, where Hk=Σ0<j k1/j and Hk(2)=Σ0<j k1/j2. In particular, we show that gather*Σk=0p-1-aka-1kHk(-1) ap\,2(Bp-1(a)-Bp-1) p, \\Σk=0p-1-aka-1kHk(2) -Ep-3(a) p, \\(2a-1)Σk=0p-1-aka-1kHk(2)2k+1 Bp-2(a) p, gather* where ap stands for the least nonnegative integer r with a rp, and Bn(x) and En(x) denote the Bernoulli polynomial of degree n and the Euler polynomial of degree n respectively. We also pose some new conjectures on congruences.

0

Turn this paper into a lesson

ArcXiv compiles a structured reading guide from this paper's metadata: plain-English importance, contributions, prerequisite concepts, which sections to read first, flashcards, and a quiz. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…