Generalizations of two cardinal inequalities of Hajnal and Juh\'asz

Abstract

A non-empty subset A of a topological space X is called finitely non-Hausdorff if for every non-empty finite subset F of A and every family \Ux:x∈ F\ of open neighborhoods Ux of x∈ F, \Ux:x∈ F\ and the non-Hausdorff number nh(X) of X is defined as follows: nh(X):=1+\|A|:A⊂ X is finitely non-Hausdorff\. Clearly, if X is a Hausdorff space then nh(X)=2. We define the non-Urysohn number of X with respect to the singletons, nus(X), as follows: nus(X):=1+\clθ(\x\):x∈ X\. In 1967 Hajnal and Juh\'asz proved that if X is a Hausdorff space then: (1) |X| 2c(X)(X); and (2) |X| 22s(X); where c(X) is the cellularity, (X) is the character and s(X) is the spread of X. In this paper we generalize (1) by showing that if X is a topological space then |X| nh(X)c(X)(X). Immediate corollary of this result is that (1) holds true for every space X for which nh(X) 2ω (and even for spaces with nh(X) 2c(X)(X)). This gives an affirmative answer to a question posed by M. Bonanzinga in 2013. A simple example of a T1, first countable, ccc-space X is given such that |X|>2ω and |X|=nh(X)ω=nh(X). This example shows that the upper bound in our inequality is exact and that nh(X) cannot be omitted (in particular, nh(X) cannot always be replaced by 2 even for T1-spaces). In this paper we also generalize (2) by showing that if X is a T1-space then |X| 2nus(X)· 2s(X). It follows from our result that (2) is true for every T1-space for which nus(X) 2s(X). A simple example shows that the presence of the cardinal function nus(X) in our inequality is essential.

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