An upper bound for weak Bk-sets

Abstract

We prove that if A⊂eq \ 1,2,…, N \ does not contain any solution to the equation x1+…+xk=y1+…+yk with distinct x1,…,xk,y1,…,yk∈ A, then |A| k3/2N1/k.

0

Turn this paper into a lesson

ArcXiv compiles a structured reading guide from this paper's metadata: plain-English importance, contributions, prerequisite concepts, which sections to read first, flashcards, and a quiz. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…