On the zeros of Riemann (z) function

Abstract

The Riemann (z) function (even in z) admits a Fourier transform of an even kernel (t)=4e9t/2θ''(e2t)+6e5t/2θ'(e2t). Here θ(x):=θ3(0,ix) and θ3(0,z) is a Jacobi theta function, a modular form of weight 12. (A) We discover a family of functions \n(t)\n≥slant 2 whose Fourier transform on compact support (-12 n, 12 n), \F(n,z)\n≥slant2, converges to (z) uniformly in the critical strip S1/2:=\|(z)|< 12\. (B) Based on this we then construct another family of functions \H(14,n,z)\n≥slant 2 and show that it uniformly converges to (z) in the critical strip S1/2. (C) Based on this we construct another family of functions \W(n,z)\n≥slant 8:=\H(14,n,2z/ n)\n≥slant 8 and show that if all the zeros of \W(n,z)\n≥slant 8 in the critical strip S1/2 are real, then all the zeros of \H(14,n,z)\n≥slant 8 in the critical strip S1/2 are real. (D) We then show that W(n,z)=U(n,z)-V(n,z) and U(n,z1/2) and V(n,z1/2) have only real, positive and simple zeros. And there exists a positive integer N≥slant 8 such that for all n≥slant N, the zeros of U(n,x1/2) are strictly left-interlacing with those of V(n,x1/2). Using an entire function equivalent to Hermite-Kakeya Theorem for polynomials we show that W(n≥slant N,z1/2) has only real, positive and simple zeros. Thus W(n≥slant N,z) have only real and imple zeros. (E) Using a corollary of Hurwitz's theorem in complex analysis we prove that (z) has no zeros in S1/2, i.e., S1/2 R is a zero-free region for (z). Since all the zeros of (z) are in S1/2, all the zeros of (z) are in R, i.e., all the zeros of (z) are real.

0

Turn this paper into a lesson

ArcXiv compiles a structured reading guide from this paper's metadata: plain-English importance, contributions, prerequisite concepts, which sections to read first, flashcards, and a quiz. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…