A Composition Theorem via Conflict Complexity

Abstract

Let (·) stand for the bounded-error randomized query complexity. We show that for any relation f ⊂eq \0,1\n × S and partial Boolean function g ⊂eq \0,1\n × \0,1\, 1/3(f gn) = (4/9(f) · 1/3(g)). Independently of us, Gavinsky, Lee and Santha newcomp proved this result. By an example demonstrated in their work, this bound is optimal. We prove our result by introducing a novel complexity measure called the conflict complexity of a partial Boolean function g, denoted by (g), which may be of independent interest. We show that (g) = ((g)) and (f gn) = ((f) · (g)).

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