Spanning trees with at most 4 leaves in K1,5-free graphs

Abstract

In 2009, Kyaw proved that every n-vertex connected K1,4-free graph G with σ4(G)≥ n-1 contains a spanning tree with at most 3 leaves. In this paper, we prove an analogue of Kyaw's result for connected K1,5-free graphs. We show that every n-vertex connected K1,5-free graph G with σ5(G)≥ n-1 contains a spanning tree with at most 4 leaves. Moreover, the degree sum condition `σ5(G)≥ n-1' is best possible.

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