A certain reciprocal power sum is never an integer

Abstract

By (Z+)∞ we denote the set of all the infinite sequences S=\si\i=1∞ of positive integers (note that all the si are not necessarily distinct and not necessarily monotonic). Let f(x) be a polynomial of nonnegative integer coefficients. Let Sn:=\s1, ..., sn\ and Hf(Sn):=Σk=1n1f(k)sk. When f(x) is linear, Feng, Hong, Jiang and Yin proved in [A generalization of a theorem of Nagell, Acta Math. Hungari, in press] that for any infinite sequence S of positive integers, Hf(Sn) is never an integer if n 2. Now let degf(x) 2. Clearly, 0<Hf(Sn)<ζ(2)<2. But it is not clear whether the reciprocal power sum Hf(Sn) can take 1 as its value. In this paper, with the help of a result of Erdos, we use the analytic and p-adic method to show that for any infinite sequence S of positive integers and any positive integer n 2, Hf(Sn) is never equal to 1. Furthermore, we use a result of Kakeya to show that if 1f(k)Σi=1∞1f(k+i) holds for all positive integers k, then the union set S∈ (Z+)∞ \ Hf(Sn) | n∈ Z+ \ is dense in the interval (0,αf) with αf:=Σk=1∞1f(k). It is well known that αf= 12(π e2π+1e2π-1-1)≈ 1.076674 when f(x)=x2+1. Our dense result infers that when f(x)=x2+1, for any sufficiently small >0, there are positive integers n1 and n2 and infinite sequences S(1) and S(2) of positive integers such that 1-<Hf(S(1)n1)<1 and 1<Hf(S(2)n2)<1+.

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