Coefficient growth in square chains
Abstract
Suppose ((·s((x2-c1)2-c2)2·s)2-ck-1)2-ck splits into linear factors over Z and ck≠0. We show that for each j and each prime p, if p≤2j-1 then p divides cj. Consequently, cj>14·2j\,\,for\,j≥5 If we also have p3\,(mod\,4) then p2j- p divides cj. Consequently, if k≥3, there exists some absolute constant λ>0 so that, cj>λ k2j\,\,for\,all\,j These estimates argue against the possibility of explicitly constructing polynomials of the given form for large k, as the coefficients quickly become too large to manipulate.
0
Turn this paper into a lesson
ArcXiv compiles a structured reading guide from this paper's metadata: plain-English importance, contributions, prerequisite concepts, which sections to read first, flashcards, and a quiz. Grounded in the abstract, never invented.