Construction Of A Rich Word Containing Given Two Factors

Abstract

A finite word w with w=n contains at most n+1 distinct palindromic factors. If the bound n+1 is attained, the word w is called rich. Let (w) be the set of factors of the word w. It is known that there are pairs of rich words that cannot be factors of a common rich word. However it is an open question how to decide for a given pair of rich words u,v if there is a rich word w such that \u,v\⊂eq (w). We present a response to this open question:\\ If w1, w2,w are rich words, m=\ w1, w2\, and \w1,w2\⊂eq (w) then there exists also a rich word w such that \w1,w2\⊂eq ( w) and w≤ m2k(m)+2, where k(m)=(q+1)m2(4q10m)2m and q is the size of the alphabet. Hence it is enough to check all rich words of length equal or lower to m2k(m)+2 in order to decide if there is a rich word containing factors w1,w2.

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