The bounds for the number of linear extensions via chain and antichain coverings
Abstract
Let (P,≤slant) be a finite poset. Define the numbers a1,a2,… (respectively, c1,c2,…) so that a1+…+ak (respectively, c1+…+ck) is the maximal number of elements of P which may be covered by k antichains (respectively, k chains.) Then the number e(P) of linear extensions of poset P is not less than Π ai! and not more than n!/Π ci!. A corollary: if P is partitioned onto disjoint antichains of size b1,b2, …, then e(P)≥slant Π bi!.
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