Schur's exponent conjecture -- counterexamples of exponent 5 and exponent 9
Abstract
There is a long-standing conjecture attributed to I Schur that if G is a finite group with Schur multiplier M(G) then the exponent of M(G) divides the exponent of G. It is easy to see that this conjecture holds for exponent 2 and exponent 3, but it has been known since 1974 that the conjecture fails for exponent 4. In this note I give an example of a group G with exponent 5 with Schur multiplier M(G) of exponent 25, and an example of a group A of exponent 9 with Schur multiplier M(A) of exponent 27.
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