The achromatic number of K6 Kq equals 2q+3 if q41 is odd
Abstract
Let G be a graph and C a finite set of colours. A vertex colouring f:V(G) C is complete provided that for any two distinct colours c1,c2∈ C there is v1v2∈ E(G) such that f(vi)=ci, i=1,2. The achromatic number of G is the maximum number achr(G) of colours in a proper complete vertex colouring of G. In the paper it is proved that if q41 is an odd integer, then the achromatic number of the Cartesian product of K6 and Kq is 2q+3.
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