Counting orientations of graphs with no strongly connected tournaments

Abstract

Let Sk(n) be the maximum number of orientations of an n-vertex graph G in which no copy of Kk is strongly connected. For all integers n, k≥ 4 where n≥ 5 or k≥ 5, we prove that Sk(n) = 2tk-1(n), where tk-1(n) is the number of edges of the n-vertex (k-1)-partite Tur\'an graph Tk-1(n), and that Tk-1(n) is the only n-vertex graph with this number of orientations. Furthermore, S4(4) = 40 and this maximality is achieved only by K4.

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