On the edge dimension and fractional edge dimension of graphs

Abstract

Let G be a graph with vertex set V(G) and edge set E(G), and let d(u,w) denote the length of a u-w geodesic in G. For any v∈ V(G) and e=xy∈ E(G), let d(e,v)=\d(x,v),d(y,v)\. For distinct e1, e2∈ E(G), let R\e1,e2\=\z∈ V(G):d(z,e1)≠ d(z,e2)\. Kelenc et al. [Discrete Appl. Math. 251 (2018) 204-220] introduced the edge dimension of a graph: A vertex subset S⊂eq V(G) is an edge resolving set of G if |S R\e1,e2\| 1 for any distinct e1, e2∈ E(G), and the edge dimension edim(G) of G is the minimum cardinality among all edge resolving sets of G. For a real-valued function g defined on V(G) and for U⊂eq V(G), let g(U)=Σs∈ Ug(s). Then g:V(G)→[0,1] is an edge resolving function of G if g(R\e1,e2\)1 for any distinct e1,e2∈ E(G). The fractional edge dimension edimf(G) of G is \g(V(G)):g is an edge resolving function of G\. Note that edimf(G) reduces to edim(G) if the codomain of edge resolving functions is restricted to \0,1\. We introduce and study fractional edge dimension and obtain some general results on the edge dimension of graphs. We show that there exist two non-isomorphic graphs on the same vertex set with the same edge metric coordinates. We construct two graphs G and H such that H ⊂ G and both edim(H)-edim(G) and edimf(H)-edimf(G) can be arbitrarily large. We show that a graph G with edim(G)=2 cannot have K5 or K3,3 as a subgraph, and we construct a non-planar graph H satisfying edim(H)=2. It is easy to see that, for any connected graph G of order n3, 1 edimf(G) n2; we characterize graphs G satisfying edimf(G)=1 and examine some graph classes satisfying edimf(G)=n2. We also determine the fractional edge dimension for some classes of graphs.

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