New bound for Roth's theorem with generalized coefficients

Abstract

We prove the following conjecture of Shkredov and Solymosi: every subset A ⊂ Z2 such that Σa∈ A\0\ 1/\|a\|2 = +∞ contains the three vertices of an isosceles right triangle. To do this, we adapt the proof of the recent breakthrough by Bloom and Sisask on sets without three-term arithmetic progressions, to handle more general equations of the form T1a1+T2a2+T3a3 = 0 in a finite abelian group G, where the Ti's are automorphisms of G.

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