Almost covering all the layers of hypercube with multiplicities
Abstract
Given a hypercube Qn := \0,1\n in Rn and k ∈ \0, …, n\, the k-th layer Qnk of Qn denotes the set of all points in Qn whose coordinates contain exactly k many ones. For a fixed t ∈ N and k ∈ \0, …, n\, let P ∈ R[x1, …, xn] be a polynomial that has zeroes of multiplicity at least t at all points of Qn Qnk, and P has zeros of multiplicity exactly t-1 at all points of Qnk. In this short note, we show that deg(P) ≥ \ k, n-k\+2t-2.Matching the above lower bound we give an explicit construction of a family of hyperplanes H1, …, Hm in Rn, where m = \ k, n-k\+2t-2, such that every point of Qnk will be covered exactly t-1 times, and every other point of Qn will be covered at least t times. Note that putting k = 0 and t=1, we recover the much celebrated covering result of Alon and Füredi (European Journal of Combinatorics, 1993). Using the above family of hyperplanes we disprove a conjecture of Venkitesh (The Electronic Journal of Combinatorics, 2022) on exactly covering symmetric subsets of hypercube Qn with hyperplanes. To prove the above results we have introduced a new measure of complexity of a subset of the hypercube called index complexity which we believe will be of independent interest. We also study a new interesting variant of the restricted sumset problem motivated by the ideas behind the proof of the above result.
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