Note on the number of antichains in generalizations of the Boolean lattice
Abstract
We give a short and self-contained argument that shows that, for any positive integers t and n with t =O(n n), the number α([t]n) of antichains of the poset [t]n is at most \[2(1+O((t3 nn)1/2))N(t,n)\,,\] where N(t,n) is the size of a largest level of [t]n. This, in particular, says that if t n/3 n as n → ∞, then α([t]n)=(1+o(1))N(t,n), giving a (partially) positive answer to a question of Moshkovitz and Shapira for t, n in this range. Particularly for t=3, we prove a better upper bound: \[α([3]n)(1+4 3/n)N(3,n),\] which is the best known upper bound on the number of antichains of [3]n.
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