Bernoulli convolutions -- 2023
Abstract
Let θ∈(1,2), and μθ be the Bernoulli convolution parametrized by θ, that is, the measure corresponding to the distribution of the random variable Σn=1∞ anθ-n, where the an are i.i.d. with probability of an=0 equal to 12. As is well known, μθ is either equivalent to the Lebesgue measure on supp(μθ), or singular. Recall that an algebraic integer >1 is called Pisot if all its other Galois conjugates are smaller than 1 in modulus. It is known that μθ is singular with μθ<1 if θ is Pisot. An algebraic integer θ greater than 1 is called a Salem number if all its other Galois conjugates are of modulus 1, except θ-1. I shall prove that (1) μθ=1 if θ is an algebraic non-Pisot number. (2) if θ is Salem, then μθ is equivalent to the Lebesgue measure on supp(μθ), with an unbounded density in Lp(supp(μθ)) for all p<∞. (3) Define \[ βθ,x,n=\#\a1… an: ∃ an+1…such that\ x=Σk=1∞anθ-k\. \] Then \[ n∞[n]βθ,x,n=θμθ\ for\ μθ-a.e. x. \] (4) Put \[ n=1∞\Σk=1nakθk ak∈\-1,0,1\\= \y0(θ)<y1(θ)<·s\, \] and \[ (θ)=n∞(yn+1(θ)-yn(θ)). \] I shall present a short proof of De-Jun Feng's famous theorem which states that (θ)=0 for all non-Pisot θ.
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