On the order of Erdos-Rogers functions
Abstract
For an integer n ≥ 1, the Erdos-Rogers function fs(n) is the maximum integer m such that every n-vertex Ks+1-free graph has a Ks-free subgraph with m vertices. It is known that for all s ≥ 3, fs(n) = (n n/ n) as n → ∞. In this paper, we show that for all s ≥ 3, equation* fs(n) = O(n\, n). equation* This improves previous bounds of order n ( n)2(s + 1)2 by Dudek, Retter and R\"odl.
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