Resolutions over strict complete intersections

Abstract

Let (Q, n) be a regular local ring and let f1, …, fc ∈ n2 be a Q-regular sequence. Set (A, m) = (Q/(f), n/(f)). Further assume that the initial forms f1*, …, fc* form a G(Q) = n ≥ 0ni/ni+1-regular sequence. Without loss of any generality assume ordQ(f1) ≥ ordQ(f2) ≥ ·s ≥ ordQ(fc). Let M be a finitely generated A-module and let (F, ∂) be a minimal free resolution of M. Then we prove that ord(∂i) ≤ ordQ(f1) - 1 for all i 0. We also construct an MCM A-module M such that ord(∂2i+1) = ordQ(f1) - 1 for all i ≥ 0. We also give a considerably simpler proof regarding the periodicity of ideals of minors of maps in a minimal free resolution of modules over arbitrary complete intersection rings (not necessarily strict).

0

Turn this paper into a full lesson

ArcXiv compiles a staged curriculum from this paper: 8-12 lessons across beginner → advanced, synthesised section guides, visuals, flashcards, a quiz, exercises, and on-demand deep dives per section. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…