On a Question of Hamkins'
Abstract
Joel Hamkins asks whether there is a 01-formula (x) such that ( φ ) is independent over PA+φ, if this theory is consistent, where this construction is extensional in φ with respect to PA-provable equivalence. We show that there can be no such extensional Rosser formula of any complexity. We give a positive answer to Hamkins' question for the case where we replace Extensionality by a weaker demand that we call Conditional Extensionality. For this case, we prove an even stronger result, to wit, there is a 01-formula (x) that is extensional and 01-flexible. We leave one important question open: what happens when we weaken Extensionality to Consistent Extensionality, i.e., Extensionality for consistent extensions?
Turn this paper into a full lesson
ArcXiv compiles a staged curriculum from this paper: 8-12 lessons across beginner → advanced, synthesised section guides, visuals, flashcards, a quiz, exercises, and on-demand deep dives per section. Grounded in the abstract, never invented.