On an iterated arithmetic function problem of Erdos and Graham

Abstract

Erdos and Graham define g(n) = n + φ(n) and the iterated application gk(n) = g(gk-1(n)). They ask for solutions of gk+r(n) = 2 gk(n) and observe gk+2(10) = 2 gk(10) and gk+2(94) = 2 gk(94). We show that understanding the case r = 2 is equivalent to understanding all solutions of the equation φ(n) + φ(n + φ(n)) = n and find the explicit solutions n = 2 · \1,3,5,7,35,47\. This list of solutions is possibly complete: any other solution derives from a number n=2 p where p ≥ 1010 is a prime satisfying φ((3p-1)/4) = (p+1)/2. Primes with this property seem to be very rare and maybe no such prime exists.

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