Number of edges with shortest cycle k in a Kautz graph

Abstract

For the Kautz digraph K(d,D), let k(d,D) be the number of oriented edges whose shortest directed cycle has length k+1, and define k(d,D) = k(d,D) - k(d,D-1). We give an exact, finite-dimensional matrix product that computes k(d,D) directly, without first computing . In particular, k(d,D)=0 for k < D/2+2. and k(d,D) is positive for every larger k up to D-1.

0

Turn this paper into a full lesson

ArcXiv compiles a staged curriculum from this paper: 8-12 lessons across beginner → advanced, synthesised section guides, visuals, flashcards, a quiz, exercises, and on-demand deep dives per section. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…