Unbounded logarithmic limsup in Erdos problem 684

Abstract

For 0 k n, write nk=uv where the primes dividing u are at most k and the primes dividing v exceed k, and let f(n) be the least k with u>n2; Erdos problem 684 asks for bounds on f(n). We resolve the problem at the order level. By a short-multiplier construction nM=tLM-1, where LM=lcm(1,…,M) and t is a multiplier of size (o(M)) extracted from a Fourier sieve, we prove that for every fixed C>1 there exist integers n with f(n)>(C-o(1)) n, hence n∞f(n) n=∞. We thus refute the widely expected upper bound f(n) n and place the order of f(n) strictly above n infinitely often. A matching polylogarithmic upper bound f(n)( n)2 is known by Alexeev, Putterman, Sawhney, Sellke, and Valiant (arXiv:2603.29961). The reduction of the multiplier sieve to a dyadic fixed- arithmetic-progression estimate, including a QM=M!/LM box parametrization, a local harmonic-height cap, and an exact-a product-shell extraction, is new. The required estimate uses Timofeev's mean-in-progressions framework together with a Burgess-based mod-p saving on the relevant prime band.

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