Fox's trapezoidal conjecture for the four-strand Turk's head knots

Abstract

Let Th(4,2n+1)=β2n+1 be the four-strand Turk's head knot, where β2n+1=σ1σ2-1σ3)2n+1. In our earlier work the Alexander polynomial of this family was reduced, after the substitution t=-z, to the factorization \[ A2n+1(z)=(1+z+·s+z2n)Dn(z)2, Dn(z)=Πr=1n (z2+42πr2n+1\,z+1). \] The remaining difficulty was to prove log-concavity of the coefficient sequence of Dn(z). In this work we prove that the coefficient sequence of Dn(z) is log-concave. The main new ingredient is a four-block smoothing theorem for products of reciprocal quartics (1+az+z2)(1+bz+z2), \: 0 a,b 4,\: a+b 4. The smoothing theorem is proved by a finite exact positivity certificate using only integer arithmetic. Combining this smoothing theorem with the trigonometric pairing r n+1-r proves that Dn(z) is log-concave for all n1. It follows that the absolute values of the coefficients of the Alexander polynomial of Th(4,2n+1) form a trapezoidal sequence. Thus Fox's trapezoidal conjecture holds for the entire family of four-strand Turk's head knots.

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