The Erdos n2/25 max-cut conjecture for small multiples of five, via a per-root-MaxCut envelope and blow-up integrality
Abstract
Erdős conjectured that every triangle-free graph on N vertices can be made bipartite by deleting at most N2/25 edges; the bound would be sharp, attained by the balanced blow-up C5[N/5]. Writing β(G) for the minimum number of edges whose deletion makes G bipartite and a(N) = \β(G):G triangle-free on N vertices\, the conjecture is a(N) N2/25, and for N=5n it reads a(5n) n2. Balogh, Clemen and Lidícký proved it for large N in the two density tails (edge density at most 0.2486 or at least 0.3197) and proved the global bound a(N) N2/23.5; the medium-density band remains open. We prove \[ a(5n) = n2 for every 1 n 40, i.e. N ∈ \5,10,…,200\. \] The proof is computer-assisted and combines three ingredients. (i) A per-root-MaxCut envelope: for the 107 triangle-free 7-root types, the mean over types of the best per-type cut is an upper bound d mono(W) U7(W) that is tight at the C5-blow-up. (ii) An order-10 flag-algebra certificate -- the per-root-MaxCut rows at 7 and 8 roots together with rooted-Horn cuts and a manifestly-PSD moment block -- bounds the envelope on the medium band, U7(W) 225+δ with an explicit rational δ≈ 4.8558×10-5, for every triangle-free graphon W of edge density in [0.2486,0.3197]. (iii) The blow-up identity β(G[t])=t2β(G) plus integrality of β turns this into β(G) n2+252n2δ for any 5n-vertex band-density G, and 252n2δ<1 for n 40; the two density tails are handled by the Balogh-Clemen-Lidícký bounds, transferred to finite N by the same blow-up. The envelope bound d mono U7 is a genuine graphon upper bound (each per-root rule is one global 2-colouring), the certificate is verified in exact rational arithmetic, the moment positivity is Razborov's flag-algebra theorem exhibited as an exact Gram factorization, and the bound is cross-checked against brute-force max-cut on all triangle-free graphs of order at most 12. The same envelope at orders 9 and 10 provably does not reach the constant needed for larger n; we explain why, and locate the all-n conjecture at a single self-tight obstruction.
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