Supersoluble groups and the probability of generating a supersoluble subgroup
Abstract
Let G be a finite group and let PU(G) denote the probability that two randomly chosen elements of G generate a supersoluble subgroup. We prove that if PU(G) ≥ 16/25 then G is supersoluble, and that the bound 16/25 is sharp, being attained by the group G = (C5 × C5) Q8, where Q8 acts faithfully and irreducibly on C5 × C5.
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