On the Jung-van der Kulk decomposition into Pascal finite factors
Abstract
Combining the Jung--van der Kulk theorem with the conjugacy invariance of the Pascal finite class, we show that every polynomial automorphism F of the plane over an arbitrary field K, satisfying F(0) = 0, decomposes into the form F = ( JF, 1) P1 … Ps, where all Pi are Pascal finite automorphisms. Since every Pascal finite automorphism has Jacobian determinant equal to 1, the diagonal factor is the only obstacle: F is a composition of Pascal finite maps if and only if JF = 1. In particular, Question~3.1 from ABCH2 has a positive answer in dimension 2 in any characteristic, which constitutes an analogue of the Exponential Generators Conjecture in positive characteristic. In characteristic p, the factors can be chosen to have an order dividing p2.
Turn this paper into a full lesson
ArcXiv compiles a staged curriculum from this paper: 8-12 lessons across beginner → advanced, synthesised section guides, visuals, flashcards, a quiz, exercises, and on-demand deep dives per section. Grounded in the abstract, never invented.