A strengthening of the Nyman-Beurling criterion for the Riemann hypothesis, 2

Abstract

Let (x)=x-[x], =(0,1). In L2(0,∞) consider the subspace generated by \a|a≥1\ where a(x):=(1ax). By the Nyman-Beurling criterion the Riemann hypothesis is equivalent to the statement ∈. For some time it has been conjectured, and proved in the first version of this paper, posted in arXiv:math.NT/0202141 v2, that the Riemann hypothesis is equivalent to the stronger statement that ∈ where is the much smaller subspace generated by \a|a∈\. This second version differs from the first in showing that under the Riemann hypothesis for some constant c>0 the distance between and -Σa=1nμ(a)e-c a na is of order ( n)-1/3.

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