An elementary proof that random Fibonacci sequences grow exponentially

Abstract

We consider random Fibonacci sequences given by xn+1= β xn+xn-1. Viswanath (viswanath), following Furstenberg (furst) showed that when β = 1, n ∞|xn|1/n=1.13..., but his proof involves the use of floating point computer calculations. We give a completely elementary proof that 1.25577 (E(|xn|))1/n 1.12095 where E(|xn|) is the expected value for the absolute value of the nth term in a random Fibonacci sequence. We compute this expected value using recurrence relations which bound the sum of all possible nth terms for such sequences. In addition, we give upper an lower

0

Turn this paper into a full lesson

ArcXiv compiles a staged curriculum from this paper: 8-12 lessons across beginner → advanced, synthesised section guides, visuals, flashcards, a quiz, exercises, and on-demand deep dives per section. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…