Surjective isometries on rearrangement-invariant spaces

Abstract

We prove that if X is a real rearrangement-invariant function space on [0,1], which is not isometrically isomorphic to L2, then every surjective isometry T:X X is of the form Tf(s)=a(s)f(σ(s)) for a Borel function a and an invertible Borel map σ:[0,1] [0,1]. If X is not equal to Lp, up to renorming, for some 1 p ∞ then in addition |a|=1 a.e. and σ must be measure-preserving.

0

Turn this paper into a full lesson

ArcXiv compiles a staged curriculum from this paper: 8-12 lessons across beginner → advanced, synthesised section guides, visuals, flashcards, a quiz, exercises, and on-demand deep dives per section. Grounded in the abstract, never invented.

Discussion (0)

Sign in to join the discussion.

Loading comments…