A simple proof of the converse of Hardy's theorem
Jose L. Cereceda
Abstract
In this paper we provide a simple proof of the fact that for a system of two spin-1/2 particles, and for a choice of observables, there is a unique state which shows Hardy-type nonlocality. Moreover, an explicit expression for the probability that an ensemble of particle pairs prepared in such a state exhibits a Hardy-type nonlocality contradiction is given in terms of two independent parameters related to the observables involved. Incidentally, a wrong statement expressed in Mermin's proof of the converse [N.D. Mermin, Am. J. Phys. 62, 880 (1994)] is pointed out.
Create a lesson
Related papers
Parallel quantum channel discrimination and numerical ranges in tensor product subspaces
Adam Bílek, Paulina Lewandowska, Ryszard Kukulski
Asymptotically Good Quantum Locally Testable Codes
William Gay, Fernando Granha Jeronimo
All causally separable quantum processes are quantum circuits with classical control of causal order
Julian Wechs, Alastair A. Abbott, Cyril Branciard
Analytic leakage suppression with a single control field: fast two-qubit gates with tunable couplers
Lukas Heunisch, Michael J. Hartmann, Aashish A. Clerk
Procrastinating einselection in non-Markovian quantum dynamics
Michael J. Moody, Tara Kalsi, Agung Budiyono et al.
Quantum Entropy Contraction and Factorization from Hypercontractivity
Li Gao, Lijun Wang