A model calculation of the value of the electromagnetic coupling constant at $q^2 = m_{Z}^{2}$

Abstract

A QCD model with an infinite number of vector mesons suggested by one of the authors is used to derive the value of the correction $\delta\alpha_{hadr}$ for $\alpha(m_{Z}^{2})$ due to the strong interactions. The result is $\delta\alpha_{hadr} = 0.0275(2)$ ; thus $\alpha(m^{2}_{Z}) = (128.96(3))^{-1}$.