The degree of the bicanonical map of a surface with pg=0
Margarida Mendes Lopes, Rita Pardini
Abstract
In this note it is shown that, given a smooth minimal complex surface of general type S with pg(S)=0, K2S=3, for which the bicanonical map is a morphism, then the degree of the bicanonical map of S is not equal to 3. This completes our earlier results, showing that if X is a minimal surface of general type with pg=0, K2>=3 such that |2KX| is free, then the bicanonical map of X can have degree 1, 2 or 4.
Create a lesson
Related papers
Morphism spaces on low degree hypersurfaces
Hrishabh Mishra
Connecting families of curves
Nathan Chen, Robert Lazarsfeld, Federico Moretti
The Last Picard Rank 1 Double-Mirror Calabi-Yau Pair?
Michał Kapustka, Marco Rampazzo, Prajwal Samal
Conductor-Discriminant Inequality for Tamely Ramified Cyclic Covers II
Connor Stewart
The Hurwitz existence problem in prime degree
Jijian Song, Hailin Wen, Zebao Zhang
Conductor-Discriminant Inequality for Tamely Ramified Cyclic Covers I
Andrew Obus, Padmavathi Srinivasan, Connor Stewart